Hi,

Let x represent the number of years so that the man will be twice as old as his son.

Now, the man is 32 years old while his son is 8 years old

32 + x = 2(8 + x)

solving for x

32 + x = 16 + 2x

16 = x, the number of years from now that the man will be twice as old as his son

CHECKING our Answer

32 + 16 = 2(8 + 16)= 2*24 = 48 

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
 The age difference is 24.

When his son is 24, he'll be twice that, in 16 years.

 

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