SOLUTION: Three brothers have ages that are consecutive odd integers. The difference between the age of the oldest and twice the age of the youngest is twenty-four less than the middle broth
Algebra.Com
Question 369533: Three brothers have ages that are consecutive odd integers. The difference between the age of the oldest and twice the age of the youngest is twenty-four less than the middle brother’s age. Find their ages.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
, , and are the ages.
The brothers are 13, 15, and 17 years old.
RELATED QUESTIONS
three brothers have ages that are consecutive odd intergers. the difference between the... (answered by vicgonzerx)
Three brothers have ages that are consecutive odd integers. The sum of the age of the... (answered by Fombitz)
The ages of three brothers are consecutive odd integers. The product of the ages of the... (answered by josgarithmetic)
the ages of three brothers are consecutive odd integers. The sum is 57. How old is the... (answered by CubeyThePenguin)
the ages of three brothers are consecutive odd integers. The sum is 57. How old is the... (answered by CubeyThePenguin)
The ages of three siblings are consecutive odd integers. The difference in the ages... (answered by stanbon,richwmiller)
I have a math word problem which I am trying to solve. It is:
"Three brothers have... (answered by josgarithmetic)
Three brothers have ages that are consecutive even integers. The product of the first and (answered by ankor@dixie-net.com)
Three brothers have ages that are consecutive even integers. The product of the first... (answered by elima)