SOLUTION: Billy is twice as old as his son. In 10 years, the ratio of their ages will be 3:5. Find their present ages.
Algebra.Com
Question 339804: Billy is twice as old as his son. In 10 years, the ratio of their ages will be 3:5. Find their present ages.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let Son be x years
Billy = 2x
after 10 years
...
son x+10
Billy = 2x +10
..
5(x+10)=3(2x+10)
5x+50==6x+30
6x-5x=50-30
x= 20 years son's age
Bill = 2x = 2*20 = 40 years
RELATED QUESTIONS
Billy is twice as old as his son. In 10 years, the ratio of their ages will be 3:5. Find... (answered by mbarugel)
Billy is twice as old as his son. in 10 years, the ratio of their ages will be 3:5. find... (answered by ewatrrr,sachi)
Billy is twice as old as his son. In 10 years, the ratio of their age will be 3:5. find... (answered by checkley77)
a man is twice as old as his son . In 10 years the sum of their ages will be 83 years.... (answered by rwm)
In three years' time, a father will be three times as old as his son. If the ratio of... (answered by ikleyn)
Age Problem
A father is 25 years older than his son. In 10 years, he will be twice as... (answered by josgarithmetic)
A father is 25 years older than his son. In 10 years, he will be twice as old as his son.
(answered by ikleyn)
Five years ago , a father awas twice as old as his son. In 4 years'time the sum of their... (answered by longjonsilver)
In 12 years, a man will be three times as old as his son; the difference of their present (answered by lwsshak3)