Question 338498: May's age is one year more than twice Bil's age. Eight years ago, the sum of their age in 10 years hence. How old are they now?
let x = age of bil
2x+1 = age of may
......age now / 8 yrs ago
bil / x / x-8
may / 2x+1 / 2x+1-8
i don't know if this is right, but i tried to answer this..
i really don't know what's the next step that i will do..
please help me..
thanks.. Answer by firstname.lastname@example.org(15649) (Show Source):