SOLUTION: Plz help me... Father's age is three years more than three times the son's age.After three years, father's age will be ten years more than twice the son's age.What is the fat

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Question 334856: Plz help me...
Father's age is three years more than three times the
son's age.After three years, father's age will be ten years more
than twice the son's age.What is the father's present age.
ANS:
I tried it like dis
let son's age be x and father's be y
So,from Ist condition v have
y=3x+3
and second we have
y+3=2(3x+3)+10
I dont know where i m getting wrong.
Found 2 solutions by Fombitz, solver91311:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You're mixing up the present and future ages in the equations.
.
.
.
I'll use F for the father's age, S for the son's.
Father's age is three years more than three times the
son's age.
1.F=3%2B3S
After three years, the father will be F+3 and the son will be S+3.
F%2B3=10%2B2%28S%2B3%29
F%2B3=10%2B2S%2B6
F%2B3=2S%2B16
2.F=2S%2B13
Now since they're both equal to F set them equal to each other and solve for S.
3%2B3S=2S%2B13
.
.
.
They using S, solve for F.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Your first equation is spot on:

But your second one has a problem. Since today the son is years old and the father is years old, in three years the son will be and the father

Then, according to the second condition:



Now add -3 to both sides of the second equation:



Now you have equal to two different things. Set them equal to each other:



And solve for

John

My calculator said it, I believe it, that settles it