SOLUTION: Plz help me...
Father's age is three years more than three times the
son's age.After three years, father's age will be ten years more
than twice the son's age.What is the fat
Algebra.Com
Question 334856: Plz help me...
Father's age is three years more than three times the
son's age.After three years, father's age will be ten years more
than twice the son's age.What is the father's present age.
ANS:
I tried it like dis
let son's age be x and father's be y
So,from Ist condition v have
y=3x+3
and second we have
y+3=2(3x+3)+10
I dont know where i m getting wrong.
Found 2 solutions by Fombitz, solver91311:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
You're mixing up the present and future ages in the equations.
.
.
.
I'll use F for the father's age, S for the son's.
Father's age is three years more than three times the
son's age.
1.
After three years, the father will be F+3 and the son will be S+3.
2.
Now since they're both equal to F set them equal to each other and solve for S.
.
.
.
They using S, solve for F.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Your first equation is spot on:
But your second one has a problem. Since today the son is
years old and the father is
years old, in three years the son will be
and the father
Then, according to the second condition:
Now add -3 to both sides of the second equation:
Now you have
equal to two different things. Set them equal to each other:
And solve for
John

My calculator said it, I believe it, that settles it

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