SOLUTION: My algebra teacher gave us this problem, I don't know how to start solving it. Please help me.
Marty is 1/3 as old as her mother. Five years ago she was only 1/5 of the age of her
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Question 333745: My algebra teacher gave us this problem, I don't know how to start solving it. Please help me.
Marty is 1/3 as old as her mother. Five years ago she was only 1/5 of the age of her mother. How old is Marty?
Found 2 solutions by ankor@dixie-net.com, Edwin McCravy:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Let m = mother's present age
Let d = daughter's present age (Marty)
:
Write an equation for each statement:
;
Marty is 1/3 as old as her mother.
d = m
or we can say
m = 3d
:
Five years ago she was only 1/5 of the age of her mother.
d - 5 = (m-5)
Mult both sides by 5, get rid of that fraction
5(d-5) = m - 5
5d - 25 = m - 5
5d = m - 5 + 25
5d = m + 20
Replace m with 3d
5d = 3d + 20
5d - 3d = 20
2d = 20
d = 10 yrs is Marty
:
:
check solution in the statement; m = 3(10) = 30 is mom
"Five years ago she was only 1/5 of the age of her mother.
10 - 5 = (30 - 5)
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!
My algebra teacher gave us this problem, I don't know how to start solving it. Please help me.
Let X = Marty's age now
Let Y = Mother's age now
Then
Marty's age five years age = (X-5)
Mother's age five years ago = (Y-5)
1/3 of Mother's age now =
1/5 of Mother's age five years ago =
>>...Marty is 1/3 as old as her mother.
Marty's age = 1/3 of Mother's age now
X =
>>...Five years ago she (Marty) was only 1/5 of the age of her mother...<<
Marty's age five years ago = 1/5 of Mother's age five years ago
(X-5) =
So we have these two equations
Multiply both sides of the first equation by 3 to clear of fractions.
Multiply both sides of the first equation by 5 to clear of fractions.
Canceling clears fractions:
Simplifying further:
Simplifying further:
Since the first equations tells us that Y = 3X we can replace the Y
in the second equation
by 3X
So Marty is 10 years old. However we need to find her
Mothers age so we can check. We use
Y = 3X
Y = 3(10)
Y = 30
So her mother is 30.
Let's check:
Marty is 1/3 as old as her mother.
Indeed 10 is 1/3 of 30
Five years ago she was only 1/5 of the age of her mother
Five years ago se was 5 and he mother was 25, and indeed
5 is 1/5 of 25.
So we know we are right.
Edwin
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