SOLUTION: Man is five times older than his son. Four years ago he was nine times older than his son. Find thier present ages.
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Question 319713: Man is five times older than his son. Four years ago he was nine times older than his son. Find thier present ages.
Answer by mananth(16949) (Show Source): You can put this solution on YOUR website!
let son be x years
father =5x
five years ago their ages were
x-5 & 5x-5
5x-5=9(x-5)
5x-5=9x-45
4x=40
x=10 years ---- son's age
Father's age = 50 years
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