SOLUTION: Paul is 12. His father is 33. How many years ago was the father 4 times as old as the son?
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Question 308450: Paul is 12. His father is 33. How many years ago was the father 4 times as old as the son?
Found 2 solutions by JBarnum, rapaljer:
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
5 years ago
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let x = number of years ago.
12-x = Paul's age x years ago
33-x = His father's age x years ago.
33-x=4(12-x)
33-x=48-4x
Add 4x to each side:
33-x+4x=48-4x+4x
33+3x=48
Subtract 33 from each side
3x=48-33
3x-15
x=5
Paul was 12-5=7
Father was 33-5=28
It checks!!
Dr. Robert J. Rapalje, Retired
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