SOLUTION: In an organization there are CE's, ME's and EE's. The sum of their ages is 2160; the average age is 36; the average age of the CE's and ME's is 39; the average age of the ME's and

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Question 30586: In an organization there are CE's, ME's and EE's. The sum of their ages is 2160; the average age is 36; the average age of the CE's and ME's is 39; the average age of the ME's and EE's is 32 8/11; the average age of the CE's and EE's is 36 2/3. If each CE had been 1 year older, each ME 6 years and each EE 7 years older, their average age would have been greater by 5 years. Find the number of each group and their average ages.
Answer by Paul(988)   (Show Source): You can put this solution on YOUR website!

Let the CE be X
Let the ME be Y
Let the EE be Z
the average age of the CE's is c years
the average age of the ME's is m years
the average age of the EE's is e years
The Sum of the total ages is 2160: Equation:
(1)
And there total average age is 36 so:
(2)
And the average of CE and ME is 39 so:
(3)
the average age of the ME’s and EE’s is 32 8/11 ---->360/11
(4)
the average age of the CE's and EE's is 36 2/3 --->110/3
(5)
"If each CE had been 1 year older, each ME 6 years and each EE 7 years older, their average age would have been greater by 5 years"
SO the equation would be:
(6)
We have 6 equations in our case:
---> Replace equation 2: --> SImplfy that:
X+Y+Z=60 (7)
ANd SInce X+Y+Z=60 replace it with equation 6.



And from equation number 1 We can replace Xc+Ym+Ze by 2160:
2160+X+6Y+7Z=2460
X+6Y+7Z=300(8)
Cross multiply the equations 3 4 and 5.
Xc + Ym = 39(X + Y) (set 1)
Ym + Ze = (360/11)(Y + Z) (set 2)
Xc + Ze = (110/3)(X + Z) (set 3)
Add all the sets to get:
2Xc + 2Ym + 2Ze = (227/3)X + (789/11)Y + (2290/33)Z
Since 33 is the lowest multiple; multiply the whole equation by 33.
and simplify
66Xc + 66Ym + 66Ze = 2497X + 2367Y + 2290Z
Apply the common factor then subsitute with the first equation:
66(2160)=2497X + 2367Y + 2290Z (9)
So after simplfying we have 7,8,9 unknowns
X+Y+Z=60 (7)
X+6Y+7Z=300 (8)
142560=2497X + 2367Y + 2290Z (9)
Subtract 8 from 7 to get:
5Y+6Z=240
Solve for Y:
y=48-1.2Z (subsitution)
Simplfy throughout using substution and elimination method to get:
X=16, Y=24, Z=20
Plug that throughout the quation and solve for the rest as averages:
If you still need help e-mail me.
Paul.








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