9(y-26)=x-26

9y-234=x-26

Subsitute:

9(92-x)-234=x-26

828-9x-234=x-26

-9x+594=x-26

-10x=-620

x=62













Hence, the man's age is 62 and his brother's age is 30.

Paul.

 

Answer by sdmmadam@yahoo.com(530)   (Show Source): You can put this solution on YOUR website!
 A man and his brother have a combined age of 92 years. 26 years ago, the man was 9 times as old as his brother. How old is the man? How old is the brother

Let the man be M yrs old and 

let the brother be B yrs old.

A man and his brother have a combined age of 92 years. 

M +B = 92  ----(1) which gives M =(92-B)  ----(*)

26 yrs ago, the man was (M-26) yrs old and 

the brother was (B-26) yrs old.

At that time the man was 9 times as old as his brother.

(M-26) = 9(B-26)    ----(2)

Using (*) in (2)that is substituting for M,we get

(92-B)-26 =9B - 9X26

92-26+9X26 = 9B+B  (grouping like terms,changing sign while changing side)

92+8X26 =10B

92+208 =10B

300 = 10B

B = 300/10 =30

Putting B = 30 in (*),we get

M =92-30 = 62

Answer:The man is now 62 yrs old and his brother is 30 years old

Verification: 26 yrs ago,the man was (62-26) = 36 yrs old and 

the brother was (30-26) = 4 yrs old and of course 36 is 9 times 4

Therefore our values are correct.

 

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