SOLUTION: ok please help me,
aead is 5 years older than Jen. Four times Jen's age increased by 3 years equals three times Ed's age diminished by 2 years. Find each person's age.
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aead is 5 years older than Jen. Four times Jen's age increased by 3 years equals three times Ed's age diminished by 2 years. Find each person's age.
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Question 29968: ok please help me,
aead is 5 years older than Jen. Four times Jen's age increased by 3 years equals three times Ed's age diminished by 2 years. Find each person's age.
ed?
Jen? Found 2 solutions by Fermat, jb007mi6:Answer by Fermat(136) (Show Source):
You can put this solution on YOUR website! Let E represent Ed's age
Let J represent Jen's age
The first part of the word problem says,
Ed is 5 years older than Jen: this becomes,
E = J + 5
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The second part of the word problem says,
Four times Jen's age increased by 3 years equals three times Ed's age diminished by 2 years: and this becomes,
4xJ + 3 = 3xE - 2
4J + 3 = 3E - 2
4J + 5 = 3E
now we substitute for E = J + 5 into the above eqn.
4J + 5 = 3(J + 5)
4J + 5 = 3J + 15
J = 10
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E = J + 5
E = 15
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You can put this solution on YOUR website! Ed-5=Jen
4(Jen)+3=3(Ed)-2
use "E" and "J" from now on...
so if J=E-5, then you can plug "e-5" everywhere you see a J in the other equation
4(e-5)=3(e)-2
4e-20=3e-2
e=18
Ed is 18 yrs old
Jen is 13 yrs old
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