SOLUTION: Rodgers age is 1 and 1/3 times Stevens age. Eight years ago, Rodger's age was twice Steven's age. Find Rodger's age
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Question 290789: Rodgers age is 1 and 1/3 times Stevens age. Eight years ago, Rodger's age was twice Steven's age. Find Rodger's age
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Rodgers age is 1 and 1/3 times Stevens age.
r = s
multiply by 3
3r = 4s
4s = 3r
s = r
:
Eight years ago, Rodger's age was twice Steven's age.
r - 8 = 2(s-8)
r - 8 = 2s - 16
r = 2s - 16 + 8
r = 2s - 8
:
Find Rodger's age
:
Replace s with r in the above equation
r = 2(r) - 8
r = r - 8
Multiply equation by 4, results
4r = 6r - 32
32 = 6r - 4r
32 = 2r
r =
r = 16 yrs is Roger's age
:
:
Check solution:
s = (16)
s = 12
"Eight years ago, Rodger's age was twice Steven's age."
16 - 8 = 2(12-8)
8 = 2(4)
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