You can
put this solution on YOUR website!Let the age of the son = x
Then the age of his father = x+30
Given,father will be only thrice as old as the son after 5 years
x+30+5 = 3(x+5)
x+35 = 3x+15
35-15 = 3x-x
20 = 2x
2x = 20
x = 20/2 = 10
Therefore the age of his father = x+30 = 10+30 = 45 years
You can
put this solution on YOUR website!f = father's age.
s = son's age.
the father is 30 years older than his son.
f = s + 30
in 5 years, the father will be 3 times as old as his son.
f + 5 = 3 * (s+5)
what is the father's age?
solve these 2 equations simultaneously to get your answer.
solve for f in terms of s in the first equation.
this is already done because the equation states that:
f = s + 30
substitute for f in the second equation.
second equation is:
f + 5 = 3 * (s + 5)
equation becomes:
s + 30 + 5 = 3 * (s + 5)
simplify to get:
s + 35 = 3*s + 15
subtract s from both sides of this equation and subtract 15 from both sides of this equation to get:
20 = 2*s
divide both sides of this equation by 2 to get:
s = 20/2 = 10
from the first equation, we get:
f = s + 30 becomes f = 10 + 30 becomes f = 40
we have:
f = 40
s = 10
substitute f = 40 and s = 10 in both original equations to see if they are true.
f = s + 30 becomes 40 = 10 + 30 becomes 40 = 40 which is true.
f + 5 = 3 * (s + 5) becomes 40 + 5 = 3 * (10 + 5) becomes 45 = 30 + 15 becomes 45 = 45 which is also true.
both equations are true confirming the values for f and s of 40 and 10 are good.
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