SOLUTION: a father is four times as old as his son. in twenty years he will be twice as old. how old are they now?

Question 258631: a father is four times as old as his son. in twenty years he will be twice as old. how old are they now?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a father is four times as old as his son. in twenty years he will be twice as old. how old are they now?
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F = 4S
(F+20) = 2(S+20)
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Substitute for "F" and solve for "S":
(4S+20) = 2S+40
2S = 20
S= 10 yrs old (the son's age)
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F= 4S = 40 yrs old (the father's age)
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Cheers,
Stan H.
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