# SOLUTION: Mary's age is twice Fred's age and one-third of Sally's age. If the sum of their ages is 99,how old are the three friends ?

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Age -> SOLUTION: Mary's age is twice Fred's age and one-third of Sally's age. If the sum of their ages is 99,how old are the three friends ?      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Age Solvers Lessons Answers archive Quiz In Depth

 Question 257635: Mary's age is twice Fred's age and one-third of Sally's age. If the sum of their ages is 99,how old are the three friends ?Answer by Theo(3464)   (Show Source): You can put this solution on YOUR website!let: m = mary's age f = fred's age s = sally's age. m = 2*f m = s/3 this leads to: f = m/2 s = 3*m sume of their ages is 99. m + f + s = 99 substitute for f and s to get: m + m/2 + 3*m = 99 combine like terms to get: 4*m + m/2 = 99 since m/2 = .5*m, this becomes: 4.5 * m = 99 divide 99 by 4.5 to get m = 22 f = m/2 = 11 s = 3*m = 66 their ages are: m = 22 f = 11 s = 66 sum of their ages is 99. mary is 22 years old fred is 11 years old sally is 66 years old