SOLUTION: Mary's age is twice Fred's age and one-third of Sally's age. If the sum of their ages is 99,how old are the three friends ?
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Question 257635: Mary's age is twice Fred's age and one-third of Sally's age. If the sum of their ages is 99,how old are the three friends ?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
let:
m = mary's age
f = fred's age
s = sally's age.
m = 2*f
m = s/3
this leads to:
f = m/2
s = 3*m
sume of their ages is 99.
m + f + s = 99
substitute for f and s to get:
m + m/2 + 3*m = 99
combine like terms to get:
4*m + m/2 = 99
since m/2 = .5*m, this becomes:
4.5 * m = 99
divide 99 by 4.5 to get m = 22
f = m/2 = 11
s = 3*m = 66
their ages are:
m = 22
f = 11
s = 66
sum of their ages is 99.
mary is 22 years old
fred is 11 years old
sally is 66 years old
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