SOLUTION: a man is 30 years old and his son is 4 years old,after how many years will the man be twice as old as his son?
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Question 244500: a man is 30 years old and his son is 4 years old,after how many years will the man be twice as old as his son?
Found 2 solutions by Earlsdon, richwmiller:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let M = the man's present age and S = the son's present age, so...
M = 30 and S = 4.
Let x = the number of years in which the man's age will be twice the son's age.
M+x = 2(S+x) Substitute M = 30 and S = 4.
30+x = 2(4+x) Simplify.
30+x = 8+2x Subtract x from both sides.
30 = 8+x Subtract 8 from both sides.
22 = x
The man will be twice the son's age in 22 years.
Check:
In 22 years, the man will be 30+22 = 52 years old.
In 22 years, the son will be 4+22 = 26 years old.
52 = 2(26)
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
In t years the man will be 30 + t years old
in t years the son will be 4+t years old.
in t years the man (30+t) will be twice 2* as old as the son (4+t)
30+t=2(4+t)
30+t=8+2t
subtract 8 from both sides
22+t=2t=t+t
and subtract t from both sides
22=t
In 22 years the man will be 52 and the son will be 26.
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