SOLUTION: A mother,aged thirty,has a seven-year-old son.in how many years,will she be twice as old as he?
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Question 227943: A mother,aged thirty,has a seven-year-old son.in how many years,will she be twice as old as he?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
30+x=2(7+x)
30+x=14+2x
x-2x=14-30
-x=-16
x=16 years from now she will be twice as old as her son.
Proof:
30+16=2(7+16)
46=2*23
46=46
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