SOLUTION: John's age is 2 years, less than three times Paul his son,s age. His son Mark is 15 years older than Paul. The sum of their ages is 103. Find the ages of John and histwo sons.

Question 227094: John's age is 2 years, less than three times Paul his son,s age. His son Mark is
15 years older than Paul. The sum of their ages is 103. Find the ages of John and histwo sons.
Found 2 solutions by josmiceli, drj:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = John's age now
Let = Mark's age now
Let = Paul's age now
given:
(1)
(2)
(3)
Substitute (1) and (2) into (3)
(3)

and, from (1)
(1)

and, from (2)
(2)

John is 52, Paul is 18, Mark is 33
check:
(3)

OK

Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
John's age is 2 years less than three times Paul his son's age. His son Mark is
15 years older than Paul. The sum of their ages is 103. Find the ages of John and his two sons.

Step 1. Let x be the age of Paul.

Step 2. Let x+15 be the age of Mark since Mark is 15 years older than Paul.

Step 3. Let 3x-2 be the age of John since John is 2 years les than 3 times Paul his son's age.

Step 4. Then, or since the sum of their sages is 103.

Step 5. Solving yields the following steps for the equation

Subtract 13 from both sides of the equation

Divide by 5 to both sides of the equation

, Then and

Check sum of ages: which is a true statement.

Step 6. ANSWER: John is 52 years old, Mark is 33 years old, and Paul is 18 years old.

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
http://www.FreedomUniversity.TV

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