# SOLUTION: Mary is "y" years old. Her father is 4 times older than Mary. Her mother is 7 years younger than her father. If the three ages add up to 101 years, find the value of "y". Find the

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 Question 22398: Mary is "y" years old. Her father is 4 times older than Mary. Her mother is 7 years younger than her father. If the three ages add up to 101 years, find the value of "y". Find the ages of Mary's parents. Thanks in advance!Found 2 solutions by elima, AnlytcPhil:Answer by elima(1433)   (Show Source): You can put this solution on YOUR website!Mary = y Her father = 4y Her mother = 4y-7 y+4y+4y-7=101 9y-7=101 9y=108 y=12 So Mary's age is 12, her father would be 4(12)=48, Her maother would be 4(12)-7=48-7=41 Hope you understand =) Answer by AnlytcPhil(1276)   (Show Source): You can put this solution on YOUR website!```Mary is "y" years old. Her father is 4 times older than Mary. Her mother is 7 years younger than her father. If the three ages add up to 101 years, find the value of "y". Find the ages of Mary's parents. >>...Mary is "y" years old...<< Translation: Mary's age = y >>...Her father is 4 times older than Mary...<< Translation: Father's age = 4y >>...Her mother is 7 years younger than her father...<< Transation: Mother's age = 4y - 7 >>...the three ages add up to 101 years...<<< Translation: y + 4y + (4y - 7) = 101 Can you solve that for y? If not post again Answers: y = 12, Mary is 12, her father is 48 and her mother is 41. Edwin AnlytcPhil@aol.com ```