SOLUTION: Kimberly is twice as old as Ryan. In 4 years, she will be 7 years older than Ryan. How old is Kimberly now?

Question 222991: Kimberly is twice as old as Ryan. In 4 years, she will be 7 years older than Ryan. How old is Kimberly now?

Answer by drj(1380) (Show Source): You can put this solution on YOUR website!
Kimberly is twice as old as Ryan. In 4 years, she will be 7 years older than Ryan. How old is Kimberly now?

Step 1. Let x be the age of Ryan

Step 2. Let 2x be the age of Kimberly

Step 3. Let x+4 be the age of Ryan in 4 years

Step 4. Let 2x+4 be the age of Kimberly in 4 years.

Step 5. 2x+4=x+4+7 since Kimberly will be 7 years older than Ryan in four years.

Step 6. Solving the equation in Step 5 yields the following steps

Solved by pluggable solver: EXPLAIN simplification of an expression

Your Result:

YOUR ANSWER

This is an equation! Solutions: x=7.
Graphical form: Equation was fully solved.
Text form: 2x+4=x+4+7 simplifies to 0=0
Cartoon (animation) form:
For tutors: simplify_cartoon( 2x+4=x+4+7 )
If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Added fractions or integers together
It becomes .

Look at .
Moved these terms to the left highlight_green%28+-x+%29

It becomes .

Look at .
Added fractions or integers together
It becomes .

Look at .
Moved

to the right of expression
It becomes .

Look at .
Removed extra sign in front of

It becomes .

Look at .
Eliminated similar terms highlight_red%28+2%2Ax+%29

replacing them with highlight_green%28+%282-1%29%2Ax+%29

It becomes .

Look at .
Remove extraneous '1' from product highlight_red%28+%282-1%29+%29

It becomes .

Look at .
Solved linear equation highlight_red%28+x-7=0+%29

equivalent to x-7 =0
It becomes .
Result:
This is an equation! Solutions: x=7.

Universal Simplifier and Solver

Done!

With then

Step 7. ANSWER: Kimberly is 14 years old.

I hope the above steps and explanation were helpful.

For Step-By-Step videos on Introduction to Algebra,
please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry please visit http://www.FreedomUniversity.TV/courses/Trigonometry.

Also, good luck in your studies and contact me at john@e-liteworks.com for your future math needs.

Respectfully,
Dr J

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