# SOLUTION: I havea problem and couldn't find a similar problem: 2 years ago a father was 4 times as old as his son. 3 years from now the father will be only 3 times as old as the son. how ol

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 Question 213442: I havea problem and couldn't find a similar problem: 2 years ago a father was 4 times as old as his son. 3 years from now the father will be only 3 times as old as the son. how old is each now? can you find a problem at least similar to this one? thank you, DestinyFound 2 solutions by stanbon, rapaljer:Answer by stanbon(57250)   (Show Source): You can put this solution on YOUR website!2 years ago a father was 4 times as old as his son. 3 years from now the father will be only 3 times as old as the son. how old is each now? =================== Let father's age NOW be "f": Let son's age NOW be "s" -------------------------------- Equation: (f-2)=4(s-2) Equation: (f+3)= 3(s+3) ------------------- Simplify both equations: f = 4s -8+2 f = 4s-6 and f = 3s+9-3 f = 3s+6 ------------------- Equate the two expressions for "f": 4s-6 = 3s+6 s = 12 yrs old (son's age NOW) --- Substitute into f = 3s+6 to solve for "f" f = 3*12+6 = 42 yrs old (father's age NOW) ============================================== Cheers, Stan H. Answer by rapaljer(4667)   (Show Source): You can put this solution on YOUR website!Let x = age of son now y= age of father now x-2= age of son 2 years ago y-2 = age of father 2 years ago x+3 = age of father 3 years from now y+3= age of father 3 years from now y-2=4(x-2) y+3=3(x+3) y-2=4x-8, so y = 4x-6 y+3=3x+9, so y=3x+6 Now, since y=4x-6 and y=3x+6, 4x-6=3x+6 x=12 Age of son now y=3x+6 y=3(12)+6 y=36+6=42 Age of father now Check: 2 years ago, son was 10 and father was 40--(four times as old!) 3 years from now, the son will be 15 and father will be 45--(three times as old!!) I would love to recommend my website to you on this, but I just don't have anything like this on it!!! R^2 Dr. Robert J. Rapalje, Retired Seminole Community College Altamonte Springs Campus Florida