SOLUTION: A man is 32 years old and his son is 7 years old. In how many years will the father be twice as old as his son?
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Question 211783: A man is 32 years old and his son is 7 years old. In how many years will the father be twice as old as his son?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
32+x=2(7+x)
32+x=14+2x
x-2x=14-32
-x=-18
x=18
In 18 years dad will be twicw as old as his son.
Proof:
32+18=2(7+18)
50=2*25
50=50
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