SOLUTION: a man is 5 times as old as his son. The difference in thier ages is 32 years. Find the man's age in 12 years' time

Question 199574: a man is 5 times as old as his son. The difference in thier ages is 32 years. Find the man's age in 12 years' time
Answer by tutorvolunteer(9) (Show Source): You can put this solution on YOUR website!
Let's use variables to form equations:
Man's age: x , Son's age: y.
x =5y , x-y = 32
Since we have 2 unknowns and 2 equations, we can solve this using a variety of methods for systems of equations. Since x=5y, we can plug this into the 2nd equation to get 4y = 32, therefore:
y = 8 , x = 40.
Since the man's age is 40, his age in 12 years' time is 52.
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