SOLUTION: mary is six years older than sue. in two years, mary will be twice as old as sue. find their present ages.

Question 195993: mary is six years older than sue. in two years, mary will be twice as old as sue. find their present ages.
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!

Let x equals Sue's Age
Therefore, x+6 will be Mary's Age (6 yrs older)

Condition: Two years hence, Mary's age will be twice as Sue:

2(Sue+2yrs)=Mary+2yrs

Combine similar terms:

, Sue's present age

Then, , Mary's Present Age

Check, (via condition)

*Note: In 2yrs, Sue will be 6 yrs old (4+2yrs), where Mary is twice as old, 12 yrs (10+2yrs).

Thank you,
Jojo
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