# SOLUTION: Hi, here is a problem I've been stuck on, please help, if possible! In 7 years, Maria will be 4 times as old as Angelica will be then. The sum of their ages is now 71. How old w

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 Question 194189This question is from textbook academic systems elementary algebra : Hi, here is a problem I've been stuck on, please help, if possible! In 7 years, Maria will be 4 times as old as Angelica will be then. The sum of their ages is now 71. How old will each of them be in 5 years? So far, I've got a chart like this: Maria: In 7 years: 4(x+7). In 5 Years: x+5 (not sure if Maria is still 4 times older than Angelica in 5 years?) Angelica: In 7 years: x+7. In 5 Years: x+5. =71 I put the equation together like this: 4(x+7) - (x+5)= 71 4(x + 28) - (x+5)= 71 4x + 28 - (x+5) = 71 4x - x +28 - 5 = 71 3x + 23 = 71 3x =48 X = 16 The solution I get is 16, but the answer at the back of the book says Angelica is 15, and Maria is 66! What did I do wrong, and what is the correct way to solve? Any help would be great, thanks! Leanne RainThis question is from textbook academic systems elementary algebra Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!In 7 years, Maria will be 4 times as old as Angelica will be then. The sum of their ages is now 71. How old will each of them be in 5 years? ------------------------------------- NOW DATA: Let Maria be "M" yrs. old Then Angel is "71-M" --------------------------- 7 yrs from NOW DATA: Maria will be "M+7" Angel will be "71-M+7" = 78-M ------------------------------- Equation based on 7 yrs. from NOW DATA: M+7 = 4(78-M) M+7 = 312 - 4M 5M = 305 M = 61 (Maria's age NOW) Angel = 71-M = 71-61 = 10 (Angel's age NOW) -------------------------------------- 5 yrs from NOW Maria will be 61+5 = 65 Angel will be 10+5 = 15 ============================= Cheers, Stan H.