# SOLUTION: Aaron is twice as old as Jack. The sum of their ages three years ago was 45 years. How old are they now? My problem is when I get the solution, the ages are backwards. Now Aa

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Age -> SOLUTION: Aaron is twice as old as Jack. The sum of their ages three years ago was 45 years. How old are they now? My problem is when I get the solution, the ages are backwards. Now Aa      Log On

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 Click here to see ALL problems on Age Word Problems Question 18658: Aaron is twice as old as Jack. The sum of their ages three years ago was 45 years. How old are they now? My problem is when I get the solution, the ages are backwards. Now Aaron = 2 Now Jack (Now Aaron - 3) + (Now Jack -3) = 45 Now Aaron + Now Jack = 51 Now Jack = 51 - Now Aaron Substitute- Now Aaron = 2(51 - Now Aaron) Now Aaron = 51 - 2 now Aaron 3 Now Aaron = 51 Aaron = 17 Jack = 34 But Aaron is supposed to be twice Jacks age not half it.Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!Try this. A = Aaron's age now. J = Jack's age now. Write two equations from the problem description. A = 2J Aaron is twice Jack's age. (A-3) + (J-3) = 45 The sum of their ages 3 years ago = 45 Simplify. A + J - 6 = 45 Add 6 to both sides. A + J = 51 Substitute A = 2J 2J + J = 51 3J = 51 Divide both sides by 3. J = 17 years. A = 2J = 2(17) = 34 years.