SOLUTION: The sum of 4 times Lottie's age and 7 times Eddie's age is 169. Eddie is one year more than twice as old ad Lottie. Find each of their ages.

Question 186499: The sum of 4 times Lottie's age and 7 times Eddie's age is 169. Eddie is one year more than twice as old ad Lottie. Find each of their ages.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Let L = Lottie's age now
Let E = Eddie's age now
:
Write an equation for each statement:
;
The sum of 4 times Lottie's age and 7 times Eddie's age is 169.
4L + 7E = 169
:
Eddie is one year more than twice as old ad Lottie.
E = 2L + 1
:
Find each of their ages.
:
Substitute (2L+1) for E in the 1st equation:
4L + 7(2L+1) = 169
:
4L + 14L + 7 = 169
:
18L = 169 - 7
L =
L = 9 yrs is Lottie's present age
then
E = 2(9) + 1
E = 19 yrs is Eddie's present age
;
;
Check solution in the statement,
"The sum of 4 times Lottie's age and 7 times Eddie's age is 169."
4(9) + 7(19) = 169, confirms our solution

RELATED QUESTIONS
how do you solve: the sum of 4 times lisa's age and 7 times janes age is 169. jane is 1... (answered by rfer)

The sum of 4 times a girls age and 7 times annoys age is 169. The boy is 1 year older... (answered by josgarithmetic)

eddies age is 4 times marco's.in 10 years eddie will be twice as ikd as marco will be.how (answered by JimboP1977)

toms's age is six years more than twice the age of his brother, Eddie. the sum of their... (answered by ikleyn,stanbon)

Eddies age is 4 times macros. in 10 years eddie will be twice as old as marco will be.... (answered by stanbon)

Eddie's age is 4 times Marco's. In 10 years Eddie will be twice as old as Marco will be.... (answered by richwmiller)

The sum of 4 times Joan's age and 3 times Jim's age is 47. Jim is 1 year less than twice... (answered by ptaylor)

Eddie's age is 4 times Marco's. In 10 years Eddie will be twice as old as Marco will be. (answered by ankor@dixie-net.com)

Shoe all work using the 5-step method to solve. Eddie's age is 4 times Marco's. In 10... (answered by mananth)