SOLUTION: A Man's age this year is three times that of his Son. If in 15 years time the Father will be twice as old as his Son, find their present ages.
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Question 182663: A Man's age this year is three times that of his Son. If in 15 years time the Father will be twice as old as his Son, find their present ages.
Found 3 solutions by kid185, Mathtut, Cally69:
Answer by kid185(2) (Show Source): You can put this solution on YOUR website!
45 and 15
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
let the age of the father and son be f and s respectively
:
.......eq 1
f+15=2(s+15)...eq 2
:
take f's value of 3s from eq 1 and plug it into eq 2
:
3s+15=2s+30
:
age of son
:
age of father
Answer by Cally69(1) (Show Source): You can put this solution on YOUR website!
Simultaneous Equations
F = Father S=Son
F - 3S = 0 (equation 1)
F - 2S = 15 (equation 2)
F - 3S = 0
- F - 2S = 15
= -1S = -15 => -15/-1 = S = 15
Eliminate Value (F)
Son = 15 years of age
F - 3S = 0 => F - 45 = 0 = Value of (F) => 45 - 0 = 45/1 = F = 45
Father = 45 years of age
To prove it.
F - 3S = 0 = 45 - 45 = 0 (equation 1)
F - 2S = 15 = 45 - 30 = 15 (equation 2)
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