Angel is twice as old as Gavin. In 3 years, Angel will be 13 years less than twice as old as Gavin. Find their ages now.
Angel's age now = A
Angel's age 3 years from now = A+3
Gavin's age now = G
Gavin's age 3 years from now = G+3
>>...Angel is twice as old as Gavin...<<
That says A = 2G
>>...In 3 years, Angel will be 13 years less than twice as old as Gavin...<<
That says:
(A+3) is 13 years less than twice (G+3)
or
A+3 = 2(G+3) - 13
A+3 = 2(G+3) - 13
A+3 = 2G+6-13
A+3 = 2G-7
A = 2G-10
So we have the system:
Substituting 2G for A in the second equation:
Subtract 2G from both sides
So the system is inconsistent. There is no solution.
Edwin