SOLUTION: Find three consecutive integers such that the sum of the first two integers is 24 more than the third integer.

Question 175395: Find three consecutive integers such that the sum of the first two integers is 24 more than the third integer.

Found 2 solutions by Mathtut, EMStelley:
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
lets call the integers a,a+1,a+2
:
a+a+1=a+2+24
:
2a+1=a+26
:

:
integers are
Answer by EMStelley(208) (Show Source): You can put this solution on YOUR website!
Call the first integer x. Then we can denote the next two by x+1 and x+2 since they are consecutive. Then the "sum of the first two" can be written as
x + (x+1)
And "24 more than the third integer" can be written as
(x+2) + 24
Thus we have the equation
x + (x+1) = (x+2) + 24
So
2x + 1 = x + 26
Subtracting x from both sides and subtracting 1 from both sides we get
x = 25
This means that the three integers are 25, 26 and 27.
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