SOLUTION: Kevin is 6 years older than Keisha. Together their ages equal four times Keishas age. How old is each? Write in algabraic sentance and solve.

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Question 175011: Kevin is 6 years older than Keisha. Together their ages equal four times Keishas age. How old is each? Write in algabraic sentance and solve.
Answer by stanbon(48546) (Show Source):
You can put this solution on YOUR website!
Kevin is 6 years older than Keisha. Together their ages equal four times Keishas age. How old is each? Write in algabraic sentance and solve.
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v = k + 6
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v+k = 4k
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Substitute or v and solve for "k".
k+6 + k = 4k
2k = 6
k = 3 (Keisha's age now)
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Since v = k+6, v = 3+6 = 9 (Kevin's age now)
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Cheers,
Stan H.