SOLUTION: jenifer is 6 years older than sue. in 4 years she will be twice as old as sue was 5 years ago. find their ages now.

Question 173722: jenifer is 6 years older than sue. in 4 years she will be twice as old as sue was 5 years ago. find their ages now.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Jennifer's age now:

Sue's age now:

Jennifer's age 4 years from now:

Sue's age 5 years ago:

Twice as old as Sue was 5 years ago

Jennifer is 6 years older than Sue: (Equation 1)

In 4 years Jennifer will be twice as old as Sue was 5 years ago: (Equation 2)

Substitute the expression for from Equation 1 into Equation 2:

Now solve for

→ → → →

If Sue is 20 years old, Jennifer must be years old.

4 years from now, Jennifer will be 30, 5 years ago, Sue was 15, and 30 is twice 15. Answer checks.
RELATED QUESTIONS
Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5... (answered by edjones)

Jennifer is 6 years older than Sue. In 4 years, She will be twice as old as Sue was 5... (answered by richwmiller)

jen is 6 years older than sue. in 4 years, she will be twice as old as sue was 5 years... (answered by palanisamy,dabanfield)

jennifer is 6 years older than sue. in 4 years, she will be twice as old as sue was 5... (answered by oberobic)

Jennifer is 6 years older than Sue. In 4 years, she will be twice as old as Sue was 5... (answered by LynnMomo)

How do I solve by using a system of two equations in two variables? Jennifer is 6... (answered by checkley77)

This question is from a worksheet. We do not have a textbook. Jennifer is 6 years older (answered by josmiceli)

barry is 8 years older than his sister. in 3 years he will be twice as old as sue was 5... (answered by algebrahouse.com)

Please help! I'm totally stuck... Jennifer is four years older than her sister, Sue. In (answered by checkley77,scott8148)