SOLUTION: A chess champion played in a 2 week tournament. At the end of the tournament she'd lost 4 more matches that she'd won. If she lost 60% of her matches, how many matches did she play

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Age -> SOLUTION: A chess champion played in a 2 week tournament. At the end of the tournament she'd lost 4 more matches that she'd won. If she lost 60% of her matches, how many matches did she play      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 171442: A chess champion played in a 2 week tournament. At the end of the tournament she'd lost 4 more matches that she'd won. If she lost 60% of her matches, how many matches did she play? Hint: 60% = 3/5
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
lets call W # of wins and L-# of losses. lets call the Total matches T
:
L=W+4--->L-W=4...eq 1
:
we know that 60%(.6)T=L and we know that 40(.4)T=W..eq 2,3
:
lets take values W and L from eq 2,3 and plug them into eq 1
:
.6T-.4T=4
:
.2T=4
:
highlight%28T=20%29total matches played