SOLUTION: A father is 4 times as old as his son. In 20 years the father will be twice as old as his son. Find the present age of each.
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Question 163065: A father is 4 times as old as his son. In 20 years the father will be twice as old as his son. Find the present age of each.
Answer by orca(409) (Show Source): You can put this solution on YOUR website!
Let x be the age of his son now, then the age of the father is 4x.
In 20 years,
The son's age = x + 20
The father's age = 4x + 20
As in 20 years the father will be twice as old as his son, we can set up an equation:
4x + 20 = 2(x + 20)
Solving the equation for x, we have
4x + 20 = 2x + 40
2x = 20
x = 10
So the age of his son now is 10, and the age of the the father now is 40.
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