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put this solution on YOUR website!A man's boyhood lasted 1/6 of his life, he played football for the next 1/8 of his life, and he married 5 years after quitting football. A daughter was born after he had been married 1/12 of his life. The daughter lived 1/2 as many years as her father. The man died 6 years after his daughter. How old was the man when he died? Use a number line to illustrate the time. Then write an equation and solve it.
:
Let x = the final age of the guy
:
Final age = Boyhood + football + 5 yr married + child's birth + child's life + 6 =
x =
x +
x + 5 +
x +
x + 6
Multiply equation by 24 to get rid of the denominators, results:
24x = 4x + 3x + 24(5) + 2x + 12x + 24(6)
:
24x = 21x + 120 + 144
:
24x - 21x = 264
x =
x = 88 yrs his final age
:
Check solution in original equation:
88 =
88 +
88 + 5 +
88 +
88 + 6
88 = 14
+ 11 + 5 + 7
+ 44 + 6
:
:
Number line (approximate)
Born + Boyhood + football + 5yr + child's birth + child's life + 6
0--------------16---------26---31------38------------------------------------------82-----88
