# SOLUTION: A man's boyhood lasted 1/6 of his life, he played football for the next 1/8 of his life, and he married 5 years after quitting football. A daughter was born after he had been marri

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 Question 159407: A man's boyhood lasted 1/6 of his life, he played football for the next 1/8 of his life, and he married 5 years after quitting football. A daughter was born after he had been married 1/12 of his life. The daughter lived 1/2 as many years as her father. The man died 6 years after his daughter. How old was the man when he died? Use a number line to illustrate the time. Then write an equation and solve it.Answer by ankor@dixie-net.com(15660)   (Show Source): You can put this solution on YOUR website!A man's boyhood lasted 1/6 of his life, he played football for the next 1/8 of his life, and he married 5 years after quitting football. A daughter was born after he had been married 1/12 of his life. The daughter lived 1/2 as many years as her father. The man died 6 years after his daughter. How old was the man when he died? Use a number line to illustrate the time. Then write an equation and solve it. : Let x = the final age of the guy : Final age = Boyhood + football + 5 yr married + child's birth + child's life + 6 = x = x + x + 5 + x + x + 6 Multiply equation by 24 to get rid of the denominators, results: 24x = 4x + 3x + 24(5) + 2x + 12x + 24(6) : 24x = 21x + 120 + 144 : 24x - 21x = 264 x = x = 88 yrs his final age : Check solution in original equation: 88 = 88 + 88 + 5 + 88 + 88 + 6 88 = 14 + 11 + 5 + 7 + 44 + 6 : : Number line (approximate) Born + Boyhood + football + 5yr + child's birth + child's life + 6 0--------------16---------26---31------38------------------------------------------82-----88