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Question 149964: Cecile is now four times as old as Daisy.Five years ago, the sum of their ages was 45.How old is each now?

: Cecile is now four times as old as Daisy.Five years ago, the sum of their ages was 45.How old is each now?


Answer by josmiceli(1903) About Me  (Show Source):
You can put this solution on YOUR website!
Cecile's age now = c
Daisy's age now = d
(1) c = 4d
Five years ago, Cecile's age was c - 5
Five years ago, Daisy's age was d - 5
(2) (d - 5) + (c - 5) = 45
sububstitute (1) into (2)
(d - 5) + (4d - 5) = 45
5d - 10 = 45
5d = 55
d = 11
c = 4d
c = 44
Daisy's age is 11 now and Cecile's age is 44 now
check:
(d - 5) + (c - 5) = 45
(11 - 5) + (44 - 5) = 45
6 + 39 = 45
45 = 45
OK
Question 149964: Cecile is now four times as old as Daisy.Five years ago, the sum of their ages was 45.How old is each now?

: Cecile is now four times as old as Daisy.Five years ago, the sum of their ages was 45.How old is each now?


Answer by Caxxx(4) About Me  (Show Source):
You can put this solution on YOUR website!
let x- Daisy's age
let y- Cecile's age
x-5 Daisy's age 5 years ago
y-5 Cecile's age 5 years ago
(x-5)+(y-5)= 45
x-5+y-5= 45=5+5
x+y= 55
y= -x+55 -- equation 1
Cecile is now four times as old as Daisy so,
4x=y --equation 2
4x=y: Substitute y from equation 1
4x= -x+55
4x+x=55
5x= 55
Divide both sides by 5 to eliminate the numerical coefficient
5x/5= 55/5
x= 11
Daisy is 11 years old.
y=-x+55
since x is equal to eleven, so
y= -11+55
y= 44
Cecile is 44 years old.