SOLUTION: Cecile is now four times as old as Daisy.Five years ago, the sum of their ages was 45.How old is each now?
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Question 149964: Cecile is now four times as old as Daisy.Five years ago, the sum of their ages was 45.How old is each now?
Found 2 solutions by josmiceli, Caxxx:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Cecile's age now =
Daisy's age now =
(1)
Five years ago, Cecile's age was
Five years ago, Daisy's age was
(2)
sububstitute (1) into (2)
Daisy's age is 11 now and Cecile's age is 44 now
check:
OK
Answer by Caxxx(4) (Show Source): You can put this solution on YOUR website!
let x- Daisy's age
let y- Cecile's age
x-5 Daisy's age 5 years ago
y-5 Cecile's age 5 years ago
(x-5)+(y-5)= 45
x-5+y-5= 45=5+5
x+y= 55
y= -x+55 -- equation 1
Cecile is now four times as old as Daisy so,
4x=y --equation 2
4x=y: Substitute y from equation 1
4x= -x+55
4x+x=55
5x= 55
Divide both sides by 5 to eliminate the numerical coefficient
5x/5= 55/5
x= 11
Daisy is 11 years old.
y=-x+55
since x is equal to eleven, so
y= -11+55
y= 44
Cecile is 44 years old.
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