SOLUTION: Kenneth's age is 5 yrs older than Alvin. Find there present ages if the product of Kenneth's age 4 yrs. from now and Alvin's age 5 yrs. ago is 51.

Question 12980: Kenneth's age is 5 yrs older than Alvin. Find there present ages if the product of Kenneth's age 4 yrs. from now and Alvin's age 5 yrs. ago is 51.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let x = Alvin's age
x+5 = Kenneth's age
x+5 + 4 = x+9 = Kenneth's age 4 yrs from now
x-5 = Alvin's age 5 years ago.

Equation:
Product of (Kenneth 4 years from now)x (Alvin 5 years ago) = 51
(x+9)(x-5) = 51

Guess what! It factors!!

x= -12, x= 8

An age cannot be negative, so
x= 8 Alvin's age
x+5 = 13 Kenneth's age

Check: In 4 years Kenneth will be 17, and 5 years ago, Alvin was 3. The product of 17*3 is 51.
It checks.

R^2 at SCC
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