# SOLUTION: Mark is 10 years younger than Larry. Larry's age in 8 years will exceed twice Mark's age 3 years ago by 4 years. How old is each now.

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 Question 129764: Mark is 10 years younger than Larry. Larry's age in 8 years will exceed twice Mark's age 3 years ago by 4 years. How old is each now.Answer by oscargut(891)   (Show Source): You can put this solution on YOUR website!Mark is 10 years younger than Larry. Larry's age in 8 years will exceed twice Mark's age 3 years ago by 4 years. How old is each now. Let Mark's age = M and Larry's age = L Mark is 10 years younger than Larry. then 1) M+10=L L+8 = Larry's age in 8 years 2(M-3) = twice Mark's age 3 years ago Larry's age in 8 years will exceed twice Mark's age 3 years ago by 4 years. then L+8=2(M-3)+4 then L+8=2M-2 then 2) L=2M-10 Then using 1) and 2) M+10=2M-10 then -M=-20 then M=20 and using 1) L=30 R: Larry's age =30 and Mark's age =20