SOLUTION: The girl is 4 years older than her brother and 22 years younger than her father. Five years ago their father was twice as old as the sum of the ages of the children. How old is the

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Question 1204657: The girl is 4 years older than her brother and 22 years younger than her father. Five years ago their father was twice as old as the sum of the ages of the children. How old is the children and father?
Found 3 solutions by mananth, josgarithmetic, math_tutor2020:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!

The girl is 4 years older than her brother and 22 years younger than her father.
Let father'sage be x and brother's age be y
y+4 =x-22
y-x= -26------------------1
Five years ago their father was twice as old as the sum of the ages of the children. How old is the children and father?
(x-5)= 2(y-5 +y+4-5)
(x-5) = 2(2y-6)
4y-12=x-5
4y-x= 7--------------------2
4y-x= 7
y-x= -26 we get
3y=33
y = 11 Brother's age
girl's age = y+4=15
x=37 father'age

The children are 11 (brother) and 15 (girl), and the father is 37 years old
Answer by josgarithmetic(39616)   (Show Source): You can put this solution on YOUR website!
GIRL                  x
BROTH.               x-4
FATH.                x+22

Very literally, .





Answer by math_tutor2020(3816)   (Show Source): You can put this solution on YOUR website!

x = brother's age 5 years ago
x+4 = sister's age 5 years ago
(x+4)+22 = x+26 = father's age 5 years ago

Five years ago their father was twice as old as the sum of the ages of the children
father's past age = 2(brother's past age + sister's past age)
x+26 = 2(x + (x+4))
x+26 = 2(2x+4)
x+26 = 4x+8
26-8 = 4x-x
18 = 3x
3x = 18
x = 18/3
x = 6
x+4 = 6+4 = 10
x+26 = 6+26 = 32

Five years ago the ages were
brother = 6
sister = 10
father = 32

Add 5 to each of those values to get the present day ages.
6+5 = 11
10+5 = 15
32+5 = 37

The present day ages are
brother = 11
sister = 15
father = 37
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