SOLUTION: 5.) The sum of the ages of Ace, Sabo, and Luffy is 27. Three years from now will be 4 times as old as Ace. IfL Uffy was twice as old as Ace 3 years ago, how old are they now?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: 5.) The sum of the ages of Ace, Sabo, and Luffy is 27. Three years from now will be 4 times as old as Ace. IfL Uffy was twice as old as Ace 3 years ago, how old are they now?      Log On

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Question 1203740: 5.) The sum of the ages of Ace, Sabo, and Luffy is 27. Three years from now will be 4 times as old as Ace. IfL Uffy was twice as old as Ace 3 years ago, how old are they now?
Found 4 solutions by ikleyn, mananth, greenestamps, josgarithmetic:
Answer by ikleyn(52810) About Me  (Show Source):
You can put this solution on YOUR website!
.
5.) The sum of the ages of Ace, Sabo, and Luffy is 27. Three years from now will be 4 times as old as Ace.
IfL Uffy was twice as old as Ace 3 years ago, how old are they now?
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Read your post as it appears at the forum.

There is a hole in it.

Find this hole and fix it.

Then re-post to the forum again.

Please do not re-post it to me in person.



Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!

The sum of the ages of Ace, Sabo, and Luffy is 27. Three years from now ******* will be 4 times as old as Ace. IfL Uffy was twice as old as Ace 3 years ago, how old are they now?
Please repost . Take care while posting




Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


Although there is a hole in your statement of the problem, logical reasoning leads to only one possible solution.

But that solution is not very interesting; so probably the given information is not correct.

The given information tells us that Luffy was twice as old as Ace 3 years ago, and that ?? will be 4 times as old as Ace 3 years from now. ?? can't be Luffy, because if he was only twice as old as Ace 3 years ago it is not possible for him to be 4 times as old 3 years from now.

So ?? must be Sabo.

So....

Let x = Ace's age 3 years ago
Then 2x = Luffy's age 3 years ago

Then x+3 is Ace's age now and 2x+3 is Luffy's age now. Since the sum of their ages is 27, Sabo's age now is 27-((x+3)+2x+3)) = 21-3x.

Then Ace's age 3 years from now will be x+6, and Sabo's age 3 years from now will be 24-3x.

3 years from now, Sabo's age will be 4 times Ace's age:

24-3x=4(x+6)
24-3x=4x+24
7x=0
x=0

ANSWERS (apparently...):
Ace's age: x+3 = 3
Luffy's age: 2x+3 =3
Sabo's age: 21-3x = 21

3 years ago their ages were 0, 0, and 18

3 years from now their ages will be 6, 6, and 24 -- satisfying the condition that Sabo will be 4 times as old as Ace then.


Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
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....., Three years from now will be 4 times as old as Ace.....
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WHAT?



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The sum of the ages of Ace, Sabo, and Luffy is 27. Three years from now will be 4 times as old as Ace. IfL Uffy was twice as old as Ace 3 years ago, how old are they now?
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Ace Sabo Luffy
a, x, L

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system%28a%2Bx%2BL=27%2C2a-L=3%29
Not much else you can do until you know what that bad sentence is.





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