SOLUTION: jack is 7 years older than mia. the sum of there ages is 53.how old is jack.

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Question 1203623: jack is 7 years older than mia. the sum of there ages is 53.how old is jack.

Found 4 solutions by mananth, Alan3354, greenestamps, josgarithmetic:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
jack is 7 years older than mia. the sum of there ages is 53.how old is jack.
Let mia's age be x years
Jack is 7 years older
so his age will be x+7 years
sum of there ages is 53
x+(x+7)=53
2x+7 =53
2x=53-7
2x = 46
x=23
mia is 23 years old
so Jack is 23+7 = 30 years old



Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
jack is 7 years older than mia. the sum of there ages is 53.how old is jack.
-------------
J - M = 7
J + M = 53
---------------------- Add
2J = 60
J = 30
M = 23

Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


You have received two good formal algebraic solutions, one using two variables and the other using one. I myself nearly always find using a single variable is easier... but it is a personal choice for each student.

If formal algebra is not required, a quick mental solution can be good problem-solving exercise.

The sum of their ages is 53, and one of them is 7 years older than the other.

So subtract 7 from the age of the older person; that subtracts 7 from the sum of their ages.

That leaves you with two people with the same age, and the sum of their ages is 63-7 = 56; so each of them is 56/2 = 28 years old.

Now add the 7 years back on to the older person's age to find the two ages are 28 and 28+7 = 35.

ANSWER: Jack (the older) is 35 years old


Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
j for Jack
j-7 for Mia

Sum of their ages is 53.





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