SOLUTION: White chocolate cost $20.00 per bar, and dark chocolate cost $25.00 per bar. If Anne bought 15 bars of chocolate for $340.00. How many bars of dark chocolate did she buy

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Question 1199606: White chocolate cost $20.00 per bar, and dark chocolate cost $25.00 per bar. If Anne bought 15 bars of chocolate for $340.00. How many bars of dark chocolate did she buy
Found 3 solutions by ikleyn, greenestamps, josgarithmetic:
Answer by ikleyn(52754)   (Show Source): You can put this solution on YOUR website!
.
White chocolate cost $20.00 per bar, and dark chocolate cost $25.00 per bar.
If Anne bought 15 bars of chocolate for $340.00, how many bars of dark chocolate did she buy?
~~~~~~~~~~~~~~~~~~~ 

Let x be the number of dark chocolate bars Anne bought.

Then the number of the white chocolate bars is 15-x.


Write the total money equation

    25x + 20*(15-x) = 340  dollars.


Simplify and find x

    25x + 300 - 20x = 340

    25x - 20x = 340 - 300

        5x    =     40

         x    =     40/5 = 8


ANSWER.  Anne bought 8 dark chocolate bars.


CHECK.  25*8 + 20*(15-8) = 200 + 140= 340 dollars, total.  ! Correct !

Solved.



Answer by greenestamps(13195)   (Show Source): You can put this solution on YOUR website!


If a formal algebraic solution is not required, here is a quick and easy informal solution method using logical reasoning and simple mental arithmetic that can be used to solve this problem and a wide range of similar problems.

(1) If all 15 bars had been white chocolate, the total cost would have been 15($20)=$300
(2) The actual cost is $340, which is an additional $40
(3) Each dark chocolate bar costs $5 more than each white chocolate bar
(4) The number of dark chocolate bars needed to make the additional $40 is $40/$5 = 8

ANSWER: She bought 8 dark chocolate bars
Answer by josgarithmetic(39613)   (Show Source): You can put this solution on YOUR website!
cost for white chocolate bars, 20w
cost for dark chocolate bars, 25d
total cost of 15 chocolate bars,

The question asks for d.

First begin simplifying the cost equation.






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