SOLUTION: Christian is twice as old as Taskie while Dark is 24 years younger than Christian. If half of Christian's age is six years ago was three less than one-half the sum of Taskie's age

Question 1193910: Christian is twice as old as Taskie while Dark is 24 years younger than Christian. If half of Christian's age is six years ago was three less than one-half the sum of Taskie's age in four years and Dark's present age, how old are these three boys?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

Christian 2t Taskie t Dark 2t-24

If half of Christian's age is six years ago was three less than one-half the sum of Taskie's age in four years and Dark's present age,
the description as an equation

Solve the equation and evaluate Christian's age and Dark's age.

----------now find the other two values.
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!

Christian is twice as old as Taskie while Dark is 24 years younger than Christian. If half of Christian's age is six years ago was three less than one-half the sum of Taskie's age in four years and Dark's present age, how old are these three boys?

Let Taskie's age be T Then Christian's is 2T, and Dark's is 2T - 24 We then get: 2T = 3T - 20 ------ Cross-multiplying 2T - 3T = - 20 - T = - 20 Taskie's age, or Christian's age: 2(20) = 40 Dark's age: 2(20) - 24 = 40 - 24 = 16

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