SOLUTION: The ages of the first and third children differ by 8 years. No child is below 2 years old, neither any of them is older than 10 years old. The second child is 7 years younger than
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Question 1187322: The ages of the first and third children differ by 8 years. No child is below 2 years old, neither any of them is older than 10 years old. The second child is 7 years younger than the fourth child. What are the ages of the four children?
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
The statement of the problem is awkward, in that usually "first" child means the first born, which makes that child the oldest.
So I am going to rewrite part of the problem to say that the second child is 7 years OLDER than the fourth.
The ages are not less than 2 and not greater than 10. If the difference between the ages of the first and third is 8 years, then their ages must be 2 and 10.
So the first child is 10 and the third is 2.
Since no child is less than 2, you now know the age of the fourth child.
And then you know the age of the second, since that child is 7 years older than the fourth.
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