SOLUTION: Charles is 1/4 as old as his father. If the sum of their ages is 45 years, how old is each?

Algebra.Com
Question 1186649: Charles is 1/4 as old as his father. If the sum of their ages is 45 years, how old is each?
Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.

Charlie's age = x


Father's age = 4x


    4x + x = 45


      x    = 9


ANSWER.  9 (Charlie) and 9*4 = 36 (father).

Solved.



RELATED QUESTIONS

John is 1/4 as old as is his father. In 8 years the sum of their ages will be 61. How old (answered by rfer)
John is 1/4 as old as his son.In 8 years' time,the sum of their ages will be 61. How old... (answered by stanbon)
Charles is one third as old as his father. In six years, Charles will be three sevenths... (answered by ankor@dixie-net.com,MathTherapy)
a father is 4 times as old as his daughter. if the sum of their ages is 75. how old is... (answered by Fombitz)
thomas is 1/4 old as his father . If the sum of their two ages is 60, then how old is... (answered by edjones)
rubesh is 30 years yunger than his father. the sum of their ages is 45. how old is his... (answered by solve_for_x)
a father is four times as old as his son. In three years the sum of their ages will be... (answered by rwm)
a father is six times as old as his son. three years ago the sum of their ages was 43.... (answered by josgarithmetic)
A man is now four times as old as his brother. five years ago the sum of their ages was... (answered by richwmiller)