SOLUTION: Six years ago,Mac's age is 20 years less than twice Kim's age. If Kim is 3 years older than Mac's. Find their ages four years from now.
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Question 1185226: Six years ago,Mac's age is 20 years less than twice Kim's age. If Kim is 3 years older than Mac's. Find their ages four years from now.
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
"Six years ago,... is,..."
No. Either drop the six years ago, or say "was".
This part: "Six years ago,Mac's age is 20 years less than twice Kim's age. "
seems to say how the first portion relates to Kim's age NOW.
IF Kim is 3 years older (NOW), then
-
----------their ages now.
In four years, Mac and Kim, 12 and 15.
Maybe problem is really supposed to be this way:
=======================================================================
Six years ago, Mac's age was 20 years less than twice Kim's age. If Kim is 3 years older than Mac's,...
=======================================================================
----------then substitute for
--------
Their ages in four more years,
=============
Mac, 24
Kim, 27
=============
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Let x be Mac's age now
Then x+3 is Kim's age now (he is 3 years older than Mac)
Then
x-6 = Mac's age 6 years ago
x+3-6 = x-3 = Kim's age 6 years ago
Mac's age 6 years ago was 20 less than twice Kim's age (then):
Their current ages are x=20 and x+3=23.
ANSWER: Their ages 4 years from now will be 20+4=24 and 23+4=27
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