Jeiselmay            5x
Sandra                x 
Eunice                x-2

Let Eunice's age be E

Then Sandra's is: E + 2, and Jeiselmay's is: 5(E + 2), or 5E + 10

Since "Jeiselmay will be 4 times as old as Eunice after 6 years," we get: 5E + 10 + 6 = 4(E + 6)

5E + 16 = 4E + 24

5E - 4E = 24 - 16

Eunice, or  

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